chose 100Ω for the resistors for my LEDs because I needed to find the optimal resistor to prevent broken LEDs. The reasoning is -- three(yellow, green, red) have 1.8 V drop. Current is 20 mA. Voltage from Arduino is 5V. Using Ohm’s law(V = I x R), the circulation to find R is:5V - 1.8V = 3.2 V = 0.02 (20mA) x R. R is 160Ω. And the resistors nearest value to 160Ω were 100Ω.
The schematic starts with input(power source) of three pins - pin 2, 3, 4. Then these three pins are connnected to three LED lights independently blinking. So I put three resistors connecting to each light with a optimal level of Ohms. It finishes with GND which circulates the system.
//Blink
//Turns an LED on for one second, then off for one second, repeatedly
//the higher the number, the slower the speed of blinking
int timer = 600;
// the setup function runs once when you press reset or power the board
void setup() {
// use for loop to initialize each pin as an output
for (int pin = 1; pin <=5; pin++)
{
pinMode(pin, OUTPUT);
}
}
// the loop function runs over and over again forever
void loop() {
//to help the pins blinking from lowest pin to highest
for (int pin = 1; pin <=5; pin++)
{
//turning on pin
digitalWrite(pin, HIGH);
//applying timer function and adjusting blinking speed
delay(timer);
//turning off pin
digitalWrite(pin, LOW);
}
//to help the pins blinking from highest pin to lowest
for (int pin = 5; pin >=1.; pin--)
{
//turning on pin
digitalWrite(pin, HIGH);
//applying timer function and adjusting blinking speed
delay(timer);
//turning off pin
digitalWrite(pin, LOW);
}
}
These three light bulbs begin to blink from left to right in the horizontal direction and blink from right to left again, repeating this action indefinitely. The speed is 600.