chose 100Ω for the resistors for my LEDs because I needed to find the optimal resistor to prevent broken LEDs. The reasoning is -- three(yellow, green, red) have 1.8 V drop. Current is 20 mA. Voltage from Arduino is 5V. Using Ohm’s law(V = I x R), the circulation to find R is:5V - 1.8V = 3.2 V = 0.02 (20mA) x R. R is 160Ω. And the resistors nearest value to 160Ω were 100Ω.
The schematic starts with input(power source) of three pins - pin 2, 3, 4. Then these three pins are connnected to three LED lights independently blinking. So I put three resistors connecting to each light with a optimal level of Ohms. It finishes with GND which circulates the system.
//Blink //Turns an LED on for one second, then off for one second, repeatedly //the higher the number, the slower the speed of blinking int timer = 600; // the setup function runs once when you press reset or power the board void setup() { // use for loop to initialize each pin as an output for (int pin = 1; pin <=5; pin++) { pinMode(pin, OUTPUT); } } // the loop function runs over and over again forever void loop() { //to help the pins blinking from lowest pin to highest for (int pin = 1; pin <=5; pin++) { //turning on pin digitalWrite(pin, HIGH); //applying timer function and adjusting blinking speed delay(timer); //turning off pin digitalWrite(pin, LOW); } //to help the pins blinking from highest pin to lowest for (int pin = 5; pin >=1.; pin--) { //turning on pin digitalWrite(pin, HIGH); //applying timer function and adjusting blinking speed delay(timer); //turning off pin digitalWrite(pin, LOW); } }
These three light bulbs begin to blink from left to right in the horizontal direction and blink from right to left again, repeating this action indefinitely. The speed is 600.